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x^2-30x-378=0
a = 1; b = -30; c = -378;
Δ = b2-4ac
Δ = -302-4·1·(-378)
Δ = 2412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2412}=\sqrt{36*67}=\sqrt{36}*\sqrt{67}=6\sqrt{67}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6\sqrt{67}}{2*1}=\frac{30-6\sqrt{67}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6\sqrt{67}}{2*1}=\frac{30+6\sqrt{67}}{2} $
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